(y^2-49)/(5y^2-30y-35)

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Solution for (y^2-49)/(5y^2-30y-35) equation:


D( y )

5*y^2-(30*y)-35 = 0

5*y^2-(30*y)-35 = 0

5*y^2-(30*y)-35 = 0

5*y^2-30*y-35 = 0

5*y^2-30*y-35 = 0

DELTA = (-30)^2-(-35*4*5)

DELTA = 1600

DELTA > 0

y = (1600^(1/2)+30)/(2*5) or y = (30-1600^(1/2))/(2*5)

y = 7 or y = -1

y in (-oo:-1) U (-1:7) U (7:+oo)

(y^2-49)/(5*y^2-(30*y)-35) = 0

(y^2-49)/(5*y^2-30*y-35) = 0

5*y^2-30*y-35 = 0

5*(y^2-6*y-7) = 0

y^2-6*y-7 = 0

DELTA = (-6)^2-(-7*1*4)

DELTA = 64

DELTA > 0

y = (64^(1/2)+6)/(1*2) or y = (6-64^(1/2))/(1*2)

y = 7 or y = -1

5*(y+1)*(y-7) = 0

(y^2-49)/(5*(y+1)*(y-7)) = 0

1*y^2 = 49 // : 1

y^2 = 49

y^2 = 49 // ^ 1/2

abs(y) = 7

y = 7 or y = -7

y in { 7}

y = -7

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